The DIMENSION of a VECTOR SPACE
- Basis and Dimension:
- Assume we have a vector space V.
- If V has basis
,
then
any subset of V with > n vectors must be dependent.
- If V has an n vector basis then
any other basis must have exactly n vectors.
- A finite-dimensional vector space V is spanned by a finite set,
with the dimension of V, dim(V), the size n of any basis for V.
- If V is not spanned by a finite set then V is
infinite-dimensional.
- Subspace Dimensions:
- A subspace H of V has a basis with
.
- If
,
some subset S of H is basis for H.
- Assume an n element subset S of V and
.
- 1.
- If S is linearly independent, then S is basis for V.
- 2.
- If S spans V, then S is basis for V.
-
dim(Nul(A)) = number of free variables for
.
-
dim(Col(A)) = number of pivot columns for A.
The RANK of a MATRIX
Assume A is an
matrix.
- The Row Space for A
- Row(A) is set of all linear combinations of rows of A.
- If ,
then A and B have the same row spaces.
- If ,
and B is in echelon form, then
the nonzero rows of B form a basis for row(A).
- The Rank Theorem
- Definition:
Rank(A) = dim(Col(A)).
- The Rank Theorem:
dim(Col(A)) = dim(Row(A));
rank(A) + dim(Nul(A)) = n.
- Row(A) = Col(AT).
- The nullity of A is
dim(Nul(A)).
- The four fundamental subspaces for A:
Row(A), Col(A), Nul(A) and Nul(AT).
- Invertible Matrix Characterizations
- If A is
invertible, the following are equivalent.
- The columns of A form a basis for Rn.
-
Col(A) = Rn.
-
dim(Col(A)) = n.
-
rank(A) = n.
-
.
-
dim(Nul(A)) = 0.
Alan C Genz
2000-07-06