- First, always factor out the greatest common factor of all the terms.
- What is Factoring a Quadratic Trinomial?
- A quadratic trinomial (polynomial of degree 2 in one variable) has the form
ax2 + bx + c, a not 0.
- The quadratic trinomial is given.
- The goal is to find numbers A, B, C, and D so that
(Ax + B)(Cx + D) = ax2 + bx + c.
- Then (Ax + B)(Cx + D) is the factored form of ax2 + bx + c.
- Then (Ax + B) and (Cx + D) are the factors of ax2 + bx + c.
- How Are the Factors (Ax + B) and (Cx + D) Found?
- By trial and error, find numbers A, B, C, and D so that
A · C = a,
A · D + B · C = b, and
B · D = c
|
- This means that
- A and C must be factors of the coefficient a,
- B and D must be factors of the coefficient c, and
- A · D + B · C must equal the coefficient b.
- Why?
- Multiplying out (Ax + B)(Cx + D) gives that
ACx2 + (AD + BC)x + BD =
|
ax2 + bx + c.
|
- Equating coefficients on left and right hand sides gives
A · C = a,
A · D + B · C = b, and
B · D = c
|
- Steps to finding A, B, C, and D
- Choose A and C such that A · C = a.
- Choose B and D such that B · D = c.
- Repeat steps 1 and 2 until A · D + B · C = b.
- Not all polynomials can be factored. If you have exhausted all the possiblities for A, B, C, and D and been unable to factor the polynomial, then the polynomial cannot be factored.
- Factoring General Trinomials
- A general trinomial will have more than one variable. For example,
3x2 + 2xy - 8y2
- which factors into
- The goal when factoring general trinomials is to find expressions A, B, C, and D such that
(A + B)(C + D) equals the given polynomial.
- Note that A, B, C, and D may be expressions containing variables.
- Steps to finding A, B, C, and D
- Choose A and C such that A · C = the first term.
- Choose B and D such that B · D = last term.
- Repeat steps 1 and 2 until A · D + B · C = the middle term.
- Polynomials with Quadratic Form
- Sometimes, higher degree polynomials can be factored when observed to have quadratic form.
- A polynomial has quadratic form if the polynomial resulting from a variable substitution is quadratic.
- For example, y4 + 5y2 + 6 has quadratic form because the resulting polynomial is quadratic when x is substituted for y2:
|
y4 + 5y2 + 6
|
|
=
|
(y2)2 + 5(y2) + 6
|
|
=
|
(x)2 + 5(x) + 6
|
x is substituted for y2
|
=
|
x2 + 5x + 6
|
resulting polynomial
|
- Then x2 + 5x + 6 factors into (x + 2)(x + 3).
- Finally, resubstituting y2 back in for x gives
y4 + 5y2 + 6 = (y2 + 2)(y2 + 3)
- Remember to check the two new factors to see if they can each be factored further.
- If One Factor of a Polynomial is Known....
- Use polynomial division (either synthetic or long) to find another factor (i.e., the quotient) of the polynomial.
- Try to factor the new factor (i.e., the quotient).
|